Q1.If the product of the zeroes of the quadratic polynomial 3x² + 5x + k is -2/3 , then
k = -3
k = -2
k = 2
k = 3
Answers
Step-by-step explanation:
Answer:
k = -2
Step-by-step explanation:
Given :
The product of the zeroes of the quadratic polynomial 3x² + 5x + k is -2/3
To find :
the value of k
Solution :
3x² + 5x + k
- x² coefficient = 3
- x coefficient = 5
- constant term = k
From the relation between zeroes and coefficients of the quadratic equation :
Product of zeroes = constant term/x² coefficient
=-2/3=k/3
= k=-2/3×3
k.= -2
Therefore, the value of k is -2
_________________________________
About Quadratic Polynomial :
✯ It is a polynomial of degree 2
✯ General form :
ax² + bx + c = 0
✯ Determinant, D = b² - 4ac
✯ Based on the value of Determinant, we can define the nature of roots.
D > 0 ; real and unequal roots
D = 0 ; real and equal roots
D < 0 ; no real roots i.e., imaginary
✯ Relationship between zeroes and coefficients :
✩ Sum of zeroes = -b/a
✩ Product of zeroes = c/a
________________________________
Answer:
k = -2
Step-by-step explanation:
product of zeroes = (constant term)/(coefficient of x^2)
-2/3 = k/3
-2 = k