Question

Q1. In a triangle the sides are given as
11 cm , 12 cm and 13 cm. Prove that
the length of the altitude is 7.25 cm
corresponding to the side having
length of 12cm​

Answer 1

ANSWER

Sides of triangle are 11,12,13

Area of triangle = s(s−a)(s−b)(s−c)

s= a+b+c/2

s=11+12+13/2

s=18

Area of triangle =18(7)(6)(5)

Area of triangle =18(7)(6)(5)=61.5

Area of triangle = 1/2 (base)(altitude)

61.5 = 1/2 ×12×(altitude)

Altitude = 10.25