Q1. IOf one root xsquare-ax-4= is negative of the other then the value of a is
a)0
b)1
c)2
d)4
Answers
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0
Let the roots of the equation x²-ax-4 = 0 be p and –p
Sum of the roots (p + (-p)) = -(-a)
Therefore, a = 0
The answer is option a
Sum of the roots (p + (-p)) = -(-a)
Therefore, a = 0
The answer is option a
Answered by
0
The answer is option a
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