Question

Q1.Let ABC be an isosceles triangle in which AB = AC. if AB=9 and BC=6cm then find the perimeter of the triangle ABC​

Answer 1

Explanation:

✬ Perimeter = 24 cm ✬

Step-by-step explanation:

Given::

∆ABC is an isosceles triangle with sides AB = AC.

Length of AB is 9 cm.

Length of BC is 6 cm.

To Find:

What is the perimeter of ∆ABC ?

Solution: Let the perimeter of triangle be x cm.

As we know that , in an isosceles triangle the two of its sides are equal to each other.

Then a/q

➟ AB = AC

AB is of 9 cm

∴ AC = 9 cm

Now , let's find the perimeter

★ Perimeter of ∆ = Sum of all sides ★

$\implies{\rm }⟹ AB + AC + BC \\ </p><p></p><p>\implies{\rm }⟹ 9 + 9 + 6 \\ </p><p></p><p>\implies{\rm }⟹ 18 + 6 \\ </p><p></p><p>\implies{\rm }⟹ 24 cm</p><p>$

Hence, the perimeter of isosceles triangle is 24 cm.

___________________

➮ Two equal sides then triangle is Isosceles.

➮ Three/All equal sides then triangle is Equilateral.

➮ No equal sides then triangle is Scalene.

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