Q1.Let ABC be an isosceles triangle in which AB = AC. if AB=9 and BC=6cm then find the perimeter of the triangle ABC
Answers
Explanation:
✬ Perimeter = 24 cm ✬
Step-by-step explanation:
Given:
∆ABC is an isosceles triangle with sides AB = AC.
Length of AB is 9 cm.
Length of BC is 6 cm.
To Find:
What is the perimeter of ∆ABC ?
Solution: Let the perimeter of triangle be x cm.
As we know that , in an isosceles triangle the two of its sides are equal to each other.
Then a/q
➟ AB = AC
AB is of 9 cm
∴ AC = 9 cm
Now , let's find the perimeter
★ Perimeter of ∆ = Sum of all sides ★
⟹ AB + AC + BC
⟹ 9 + 9 + 6
⟹ 18 + 6
24 cm
Hence, the perimeter of isosceles triangle is 24 cm.
___________________
➮ Two equal sides then triangle is Isosceles.
➮ Three/All equal sides then triangle is Equilateral.
➮ No equal sides then triangle is Scalene.
P = 2a + b
we know AB = AC
LET AB= a
BC = b
P = 2(9) + 6
= 18+6
= 24cm
hope it will help u