Question

Q1. Multiply 3/7by the reciprocal of-5/7​

Answer 1

To find : to multiply one rational number with the reciprocal of another rational number .

Given rational numbers : $\frac{3}{7} \ and \ \frac{-5}{7}$

Solution :

• As we know , reciprocal of a fraction is a interchanging the places of numerator and denominator upside down .
• To solve the above question we need to find reciprocal of  $\frac{-5}{7}$ .

• therefore, reciprocal of $\frac{-5}{7} \ is\ \frac{-7}{5}$
• now , to find product we multiply   $\frac{3}{7} \ and \ \frac{-7}{5}$  .

    ⇒                        $\frac{3}{7} \times (\frac{-7}{5})$

        on simplifying we get,

                                 $= \frac{3}{5}$  

     Hence , $\frac{3}{5}$ is the required product of  $\frac{3}{7}$ and reciprocal of  $\frac{-5}{7}$

Answer 2

• As per the given question we have to determine the given value.

        Given data:-$\frac{3}{7}$ reciprocal of $\frac{-5}{7} .$

        To find:- to multiply one rational number with the reciprocal of another rational number.

          Solution:-

• As we know, the reciprocal of a fraction is interchanging the places of numerator and denominator upside down.

• To solve the above question we need to find reciprocal of $\frac{-5}{7}$   .

• Therefore, reciprocal of $\frac{-5}{7}$ is $\frac{-7}{5}$

         now , to find product we multiply $\frac{3}{7}$ and $\frac{-7}{5}$

                 $\frac{3}{7} \times(\frac{-7}{5} )\\=\frac{3}{5} .$

       Hence we will get the value  $\frac{3}{5}$,