Question

Q1.one year ago,a mother was 8 times as old as her daughter. At present, the mother's age is equal to the square of the daughter's age. find the present age of the mother​.

Answer 1

Step-by-step explanation:

Answer:

Presently mother is 49 years old and daughter is 7 years old.

Step-by-step explanation:

Let,

Present age of Daughter = x

Present age of Mother = x²

One year ago,

Age of Daughter = x - 1

Age of Mother = x² - 1

Also,

Mother was 8 times as old as her daughter.

⟶ x² - 1 = 8(x - 1)

⟶ x² - 1 = 8x - 8

⟶ x² - 8x - 1 + 8 = 0

⟶ x² - 8x + 7 = 0

⟶ x² - 7x - x + 7 = 0

⟶ x(x - 7) - 1(x - 7)

⟶ (x - 7)(x - 1)

⟶ x = 7 or x = 1

Daughter's present age = 7 years.

_______________________________

★ Mother's present age =

⟶ x²

⟶ (7)²

⟶ 49

Therefore, presently mother is 49 years old and daughter is 7 years old.