Q1. Out of 800 families with 4 children each, how many families would be expected to have – (i) 2 boys and 2 girls (ii) at least one boy (iii) no girls (iv) at most 2 girls? Assume equal probabilities for boys and girls.
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2
Answer:
250
400
Step-by-step explanation:
With 5 children in 1 family there can be 6 cases
5 Boys - No girls - 1
4 Boys 1 Girl - 5
3 Boys 2 Girl - 10
2 Boys 3 Girl 10
1 boys 4 girls 5
No boys 5 girls 1
Total number of cased = 2⁵ = 32 or 1 + 5 + 10 + 10 + 5 + 1 = 32
Probability of 3 boys & 2 girls = 10/32
With 800 family = (10/32) * 800 = 250
250 Families would be expected to have 3 boys and 2 Girls
Almost 2 girls means , No girl , 1 Girl & Two Girls
= 1 + 5 + 10 = 16
Probability of almost 2 girls = 16/32 = 1/2
With in 800 family = (1/2) * 800 = 400
400 Families would be expected to have almost 2 girls
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