Question

Q1 ,Q2 charges are separated by distance d. F is the force between them . The value of Q2 is halved . To have a same force between the changes,the distance of separation should be

Answer 1

Answer:

d/√2 units

Explanation:

initially

F=k*Q1*Q2/d^2

on changing Q2 to half of Q2

F'=k*Q1*Q2/(2*d'^2)

on applying given condition that F=F'

k*Q1*Q2/d^2 = k*Q1*Q2/(2*d'^2)

2*d'^2 = d^2

d' = ((d^2)/2)^(1/2)

d' = d/√2