Question

Q1. Show that x^2+4x+7 has no zero.

Q2. Using Remaineder Theorem, show that polynomial p(x)=3X4-4X3-3x+4 is a multiple of x-1.

Q3. If 2x-√y=10 and xy= -√y, find value of 4x^2+7y^2.

Q4. Show that if 2(a^2+b^2)=(a+b)^2, then a=b

Please help quickly..answer fast thnks

Answer 1

      Q.no-2 x-1=0
                  x=1
p(x)=3*4-4*3-3x+4
p(1)=3*4-4*3-3*1+4
     =12-12-3+4
     =16-15
     =1 ans

you are riti . i am raushan maharana

Answer 2

 Q.no-2 x-1=0
                  x=1
p(x)=3*4-4*3-3x+4
p(1)=3*4-4*3-3*1+4
     =12-12-3+4
     =16-15
     =1 ans