Math, asked by as55310, 8 months ago

Q1. Solve:

a) 3(y-1) = 2(2y-6)

b) 8x/3 + 4 = 12

c) 12a + 4 = 40

d) 3(2x – 1) + 5 = 14​

Answers

Answered by azaan9657
1

Answer:

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Step-by-step explanation:

a) 3(y-1)=2(2y-6)

3y-3=4y-12

-y=-9

y=9

b) 8x/3 +4= 12

8x/3 = 8

8 cancels both sides

x/3= 1

x = 3

c) Add '-4' to each side of the equation.

4 + -4 + 12a = 40 + -4

Combine like terms: 4 + -4 = 0

0 + 12a = 40 + -4

12a = 40 + -4

Combine like terms: 40 + -4 = 36

12a = 36

Divide each side by '12'.

a = 3

d) 3 (2x - 1)+5= 14

6x-3+5=14

6x+2=14

6x=12

x=2

Answered by AzeemFatmaZaidi
0

Step-by-step explanation:

here is your answer.

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