Q1. Solve:
a) 3(y-1) = 2(2y-6)
b) 8x/3 + 4 = 12
c) 12a + 4 = 40
d) 3(2x – 1) + 5 = 14
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Step-by-step explanation:
a) 3(y-1)=2(2y-6)
3y-3=4y-12
-y=-9
y=9
b) 8x/3 +4= 12
8x/3 = 8
8 cancels both sides
x/3= 1
x = 3
c) Add '-4' to each side of the equation.
4 + -4 + 12a = 40 + -4
Combine like terms: 4 + -4 = 0
0 + 12a = 40 + -4
12a = 40 + -4
Combine like terms: 40 + -4 = 36
12a = 36
Divide each side by '12'.
a = 3
d) 3 (2x - 1)+5= 14
6x-3+5=14
6x+2=14
6x=12
x=2
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