Question

Q1.solve by elimination method 5x-8y+1=0 ; 3x- 24/5 y + 3/5=0.

Answer 1

Explanation:

Given

We have given two Equations : 5x-8y+1=0 ; 3x- 24/5 y + 3/5=0

To Find

We have to find the value of x and y

$\sf\huge \mathbb{\underline{\underline{{Solution}}}} </p><p>Solution</p><p>$

➙5x-8y+1=0-----------×3

➙3x-24/5y+3/5=0----×5

New Equation obtained

➙15x-24y= -3

➙15x-24/y= -3[ -3/5×5= -3]

➙(-)(+)\:\:(+)(−)(+)(+)

____________

-24y-24y= -6

-48y= -6

y= 6/48= 1/8

y= 1/8

Put y's value into this equation

➙5x-8y= -1

➙5x-8(1/8)=-1

➙5x-1= -1

➙5x= -1+1=0

➙x=0

x=0

Check:

➙5x-8y= -1

Taking LHS

➙5(0)-8×1/8

➙0-1

= -1

Since,LHS =RHS(Verified).

Extra information=>

Elimination method is a way of eliminating one variable from equation of two variable so that we can find value of one variable.

Elimination means =>To Remove

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