Q1.solve by elimination method 5x-8y+1=0 ; 3x- 24/5 y + 3/5=0.
Answers
Explanation:
Given
We have given two Equations : 5x-8y+1=0 ; 3x- 24/5 y + 3/5=0
To Find
We have to find the value of x and y
➙5x-8y+1=0-----------×3
➙3x-24/5y+3/5=0----×5
New Equation obtained
➙15x-24y= -3
➙15x-24/y= -3[ -3/5×5= -3]
➙(-)(+)\:\:(+)(−)(+)(+)
____________
-24y-24y= -6
-48y= -6
y= 6/48= 1/8
y= 1/8
Put y's value into this equation
➙5x-8y= -1
➙5x-8(1/8)=-1
➙5x-1= -1
➙5x= -1+1=0
➙x=0
x=0
Check:
➙5x-8y= -1
Taking LHS
➙5(0)-8×1/8
➙0-1
= -1
Since,LHS =RHS(Verified).
Extra information=>
Elimination method is a way of eliminating one variable from equation of two variable so that we can find value of one variable.
Elimination means =>To Remove
Answer:
Given System of equations are:
5x−8y+1=0
3x−
5
24
y+
5
3
=0
From equation (2) will get
15x−24y+3=0
Now from equation (1) and (2) will have:
a
2
a
1
=
15
5
,
b
2
b
1
=
−24
−8
,
c
2
c
1
=
3
1
⇒
a
2
a
1
=
3
1
,
b
2
b
1
=
3
1
,
c
2
c
1
=
3
1
Therefore, system of equations have Infinitely many solutions.