Question

Q1.solve by elimination method 5x-8y+1=0 ; 3x- 24/5 y + 3/5=0​.

Answer 1

Explanation:

Given

We have given two Equations : 5x-8y+1=0 ; 3x- 24/5 y + 3/5=0

To Find

We have to find the value of x and y

$\sf\huge \mathbb{\underline{\underline{{Solution}}}} </p><p>Solution</p><p>$

➙5x-8y+1=0-----------×3

➙3x-24/5y+3/5=0----×5

New Equation obtained

➙15x-24y= -3

➙15x-24/y= -3[ -3/5×5= -3]

➙(-)(+)\:\:(+)(−)(+)(+)

____________

-24y-24y= -6

-48y= -6

y= 6/48= 1/8

y= 1/8

Put y's value into this equation

➙5x-8y= -1

➙5x-8(1/8)=-1

➙5x-1= -1

➙5x= -1+1=0

➙x=0

x=0

Check:

➙5x-8y= -1

Taking LHS

➙5(0)-8×1/8

➙0-1

= -1

Since,LHS =RHS(Verified).

Extra information=>

Elimination method is a way of eliminating one variable from equation of two variable so that we can find value of one variable.

Elimination means =>To Remove

Answer 2

Answer:

Given System of equations are:

5x−8y+1=0

3x−

5

24

y+

5

3

=0

From equation (2) will get

15x−24y+3=0

Now from equation (1) and (2) will have:

a

2

a

1

=

15

5

,

b

2

b

1

=

−24

−8

,

c

2

c

1

=

3

1

⇒

a

2

a

1

=

3

1

,

b

2

b

1

=

3

1

,

c

2

c

1

=

3

1

Therefore, system of equations have Infinitely many solutions.