Question

Q1. SOLVE PLS

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Answer 1

Answer:

khya

Step-by-step explanation:

we cannot understand this question can u say the answer for it

Answer 2

Step-by-step explanation:

Whenever we are given circuit containing more than one battery, it is better to apply KVL to find current across each resistors..

For Loop - 1 [Anti-clockwise] :

→ 80 - 20I + 20 - 20I₁ = 0

→ 100 - 20I - 20I₁ = 0

→ 20 (I + I₁) = 100

→ I + I₁ = 5

→ I₁ = 5 - I _______ [Eq. 1]

For Loop - 2 [Clockwise] :

→ 20 - 20I₁ + 30I₂ = 0

→ 10 (2I₁ - 3I₂) = 20

→ 2I₁ - 3I₂ = 2

→ 2I₁ - 3 (I - I₁) = 2 (∵ I = I₁ + I₂)

→ 2I₁ - 3I + 3I₁ = 2

→ -3I + 5I₁ = 2 _______ [Eq. 2]

By comparing both equations,

→ -3I + 5 (5 - I) = 2

→ -3I + 25 - 5I = 2

→ -8I = -23

→ I = 23/8 A

By substituting the value of I into first equation,

→ I₁ = 5 - 23/8

→ I₁ = (40 - 23) / 8

→ I₁ = 17/8 A

We know that, I = I₁ + I₂

→ 23/8 - 17/8 = I₂

→ I₂ = 6/8

→ I₂ = 3/4 A

• A] Current through 20Ω (I) = 23/8 A
• B] Current through 30Ω (I₂) = 3/4 A
• C] Current through 20Ω (I₁) = 17/8 A