Q1.Solve the trigo. equartion ?
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Heya mate, Here is ur answer
Taking LHS
(sin A + Cosec A)^2 +(cos A+ sec)^2
= sin ^2 A + cosec ^2 A + 2 sin A cosec A + cos ^2 A + sec ^2 A + 2cos A sec A
= sin ^2 A+Cos ^2 A + + cosec ^2 A + sec^2 A + 2 sin A cosec A + 2 cos A sec A
= 1 + (1 + cot ^2 A) + (1 + tan^2 A) + 2 sin A ×1/sinA +2 cos A ×1/cos A
= 1 + 1 + cot ^2 A + 1 + Tan^2 A + 2 + 2
= 7+ Tan^2 A + cot ^2 A
= RHS
---
⏩(a+b)^2 = a^2 +b^2 +2ab
⏩sin ^2 A+ cos ^2 A = 1
⏩ cosec^2 A =1+ cot^2 A
⏩ sec^2 A =1+Tan^2 A
⏩Cosec A =1/Sin A
⏩sec A =1/cos A
======================
Warm regards
@Laughterqueen
Be Brainly ✌✌✌
Taking LHS
(sin A + Cosec A)^2 +(cos A+ sec)^2
= sin ^2 A + cosec ^2 A + 2 sin A cosec A + cos ^2 A + sec ^2 A + 2cos A sec A
= sin ^2 A+Cos ^2 A + + cosec ^2 A + sec^2 A + 2 sin A cosec A + 2 cos A sec A
= 1 + (1 + cot ^2 A) + (1 + tan^2 A) + 2 sin A ×1/sinA +2 cos A ×1/cos A
= 1 + 1 + cot ^2 A + 1 + Tan^2 A + 2 + 2
= 7+ Tan^2 A + cot ^2 A
= RHS
---
⏩(a+b)^2 = a^2 +b^2 +2ab
⏩sin ^2 A+ cos ^2 A = 1
⏩ cosec^2 A =1+ cot^2 A
⏩ sec^2 A =1+Tan^2 A
⏩Cosec A =1/Sin A
⏩sec A =1/cos A
======================
Warm regards
@Laughterqueen
Be Brainly ✌✌✌
kulbhushan12345:
TnQ... so much
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