Question

Q1. Subtract :


a) 4xy2
from 3xy2

b) -2x2y + 3xy2
from 8x2y

c) 8a + 3ab -2b + 7 from 14a -5ab + 7b – 5


Q2. Subtract the sum 5y2 + y -3 and y2 – 3y + 7 from 6y2 + y

Q3. How much less is 2a2 + 1 from 3a2 – 6 ?​

Answer 1

Answer:

question 2 answer is 4y2+4y-4