Question

Q1.t7=10 t13=34 find tt10.

Answer 1

Explanation:

Given

We have given t₇ = 10 & t₁₃ = 34

To Find

We have to find t₁₀ = ?

SOLUTION:

We have two term given t₇ = 10 & t₁₃ = 34

➙t₇ can be written as : a+6d

➙ t₁₃ can be written as a+12d

Now, a+6d = 10

\:\:\:\:\:\:\: a+12d=34

\:\:\:\: (-)(-)\:(-)(−)(−)(−)

\:\:\:\: ___________

\:\:\:\: -6d= -24

\:\:\:\: 6d= 24

\:\:\:\: d=24÷6=4

Hence,d(common difference ) is 4

Now,put d's value into this equation

➙a+6d=10

➙a+6(4)=10

➙a+24=10

➙a=10-24=-14

a= -14

We have a = -14 & d=4

Now,we havebe to find t₁₀

➙t₁₀ can be written as a+9d

➙a+9d= -14+9(4)

➙-14+36=22

Hence,t₁₀ is 22.

Answer 2

Answer:

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