Question

Q1.The angle of elevation and the angle of depression of the top and foot of the monument, when observed from a point on the roof of a five-storied building of Mihir are 60° and 30° respectively. If the height of building is 16 metre, what will be the height of the monument ??????​

Answer 1

Step-by-step explanation:

Answer:

Refer to the Attachment for the diagram.

Important Interpretations from the diagram:

AB = CD = 16 m

AD = BC (Parallel and Equal)

DE = 'x'

Height of Monument = CE = (x+CD)

∠DAC = ∠ACB = 30° (Adjacent Angles)

From the interpretation, we get:

⇒ Height of monument = x + 16 m.

Consider ΔADE,

$\begin{gathered}\implies Tan\:60 = \dfrac{ED}{AD}\\\\\\\implies \sqrt{3} = \dfrac{x}{AD}\\\\\\\implies \boxed{ \bf{ x = AD\sqrt{3}}}\end{gathered} </p><p></p><p>$

Consider ΔABC,

$\begin{gathered}\implies Tan\:30 = \dfrac{AB}{BC}\\\\\\\implies \dfrac{1}{\sqrt{3}} = \dfrac{16}{AD}\\\\\\\implies \boxed{ \bf{ AD = 16\sqrt{3}}}\end{gathered} </p><p>$

Substituting the value of AD, we get:

⇒ x = AD√3

⇒ x = ( 16√3 ) × √3

⇒ x = 16 × 3

⇒ x = 48 m.

Hence the height of the monument is:

⇒ (x + 16) = (48 + 16) = 64 m.

Answer 2

Answer:

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