Question

Q1. The curved surface area of a cone is 4070 cm2 and its radius is 35 cm Find
itsi) slant height
ii) volume​

Answer 1

Done by Aritra Kar.

Given: -

$Curved \: Surface \: Area \: of \: a \: cone(C.S.A) = 4070 \ {cm}^{2} \\ Radius(r) \: of \: the \: cone = 35cm$

$To \: find:-$

$Slant \: height \: (l) \: and \: volume \: (v) \: of \: the \: cone$

$So, \: By \: the \: problem :- \\ csa = 4070 {cm}^{2} \\ plot \: the \: formula \: of \: C.S.A\: \\ = > \pi \: rl = 4070 \\ plot \: the \: of \: each \: variable. \\ = > \frac{22}{7} \times 35 \times l = 4070 \\ = > l = \frac{4070}{22 \times 5} \\ = > 37cm$

$Formula:-\\Volume = \frac{1}{3} \pi\:{r}^{2} h\\</p><p>So, \: plot \: the \: value \: of \: the \: variables: - \\ > (\frac{1}{3} \times \frac{22}{7} \times 35 \times 35 \times 37) {cm}^{3} \\ = > \frac{22 \times35 \times 35 \times 37 }{3 \times 7} \\ = > \frac{22 \times 35 \times 5 \times 37}{3} \\ = > \frac{142450}{3} \\ = > 47483.33..... \\ = > 47483.33$

Answer: -

$So ,\: slant \: height(l) = 37cm \\ and \\ volume \: (v) = 47483.33$