Question

Q1.the digit in the tens place of a 2 digit number is 3 more than the digit in the units place. let the digit at units place be b. then the number is​?

Answer 1

Explanation:

✬ Number = 30 + 11b ✬

Step-by-step explanation:

Given:

A two digit number.

Ten's place digit is 3 more than the unit's place digit.

Digit at unit place is b.

To Find:

What is the number ?

Solution: As we know that

A two digit number is 10 × digit in ten’s place + digit in unit’s place.

➟ Ten's place digit = 3 more than b

➟ Ten's place digit = ( b + 3 )

Now the number will be

$\implies{\rm }⟹ 10 × (ten's digit) + unit's digit$

$\implies{\rm }⟹ 10 × (b + 3) + b$

$\implies{\rm }⟹ 10b + 30 + b$

$\implies{\rm }⟹ 30 + 11b$

Hence, the two digit number is 30 + 11b.

Answer 2

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(a) 11b + 30

From the question it is given that,

Let the digit at units place be b.

The digit in the tens place of a two digit number is 3 more than the digit in the units place = 3 + b

So, the number = 10 (3 + b) + b = 30 + 10b + b = 30 + 11b

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