Question

Q1.The electric field at the centre O of equilateral triangle having charge of 2 mu C at each of its vertex is:

Answer 1

Explanation:

Given:

Equilateral ∆ with 2\:\mu C2μC charges at each vertex.

To find:

Net field intensity at centre O?

Calculation:

Here centre O can be assumed as the centroid.

Now, each of the charge exerts an field intensity as follows:

$\rm \: E = \dfrac{kq}{ {r}^{2} }</p><p>$

$\rm \implies \: E = \dfrac{k(2 \times {10}^{ - 6}) }{ {r}^{2} }$

Now, from the diagram, we can see :

E1, E2, E3 are equal.

The E vectors are at 120° to one another.

Now, when three equal vectors are inclined at 120° to one another, their net resultant becomes zero.

So, net field intensity at centre is zero.