Question

Q1)The electronic configuration of two elements A and B are 1s² 2s² 2p⁴ and 1s² 2s² 2p⁶ 3s² respectively.

Write down the following information from the above data

(i) metallic and non-metallic character A and B,

(ii) formula and nature of bond present in the compound formed between A and B (iii) Predict whether A is oxidizing or reducing agent​

Answer 1

Answer:

A has non metallic character

B has metallic character

FORMULA

AB

ionic bond

A will be oxidizing B

HERE A has 4 electrons in the valance shell or u can say in 2p orbital

it will gain 2 electrons to attain stability and completely fill 2p orbital as acceptors are non metals ..hence A IS NON METALLIC IN NATURE

while B will donate 2 electrons from 3s orbital to become stable

METALS ARE ELECTRON DONORS hence B is a metal

here both have valency 2 each

hence formula is AB

AS plus 2 of B is balanced by -2 of A

as bonds are formed due to give and take of electrons ..bond is due electro static force of attraction with is strong ionic bond

as A GAINS ELECTRONS FROM METAL IT OXIDIZES IT TO FORM METAL OXIDES