Question

Q1.The first term of an A.P is -1 and d=2 them 10th term is.

Answer 1

Step-by-step explanation:

Given :-

The first term of an AP is - 1 and common difference is 2.

To Find :-

What is the 10th term of an AP.

Formula Used :-

$\begin{gathered}\mapsto \sf\boxed{\bold{\pink{T_n =\: a + d(n - 1)}}}\\\end{gathered} </p><p>$

where,

a = First term of an AP

d = Common difference

n = Number of terms

Solution :-

Given :

$\begin{gathered}\bigstar\: \: \rm{\bold{First\: term\: (a) =\: - 1}}\\\end{gathered} </p><p></p><p>$

$\begin{gathered}\bigstar\: \: \rm{\bold{Common\: difference\: (d) =\: 2}}\\\end{gathered} </p><p></p><p>$

$\begin{gathered}\bigstar\: \: \rm{\bold{Number\: of\: terms\: (n) =\: 10}}\\\end{gathered} </p><p>$

According to the question by using the formula we get,

$\longrightarrow \sf T_{10} =\: - 1 + 2(10 - 1)$

$\longrightarrow \sf T_{10} =\: - 1 + 2(10) - 2(1)$

$\longrightarrow \sf T_{10} =\: - 1 + 20 - 2$

$\longrightarrow \sf T_{10} =\: 19 - 2</p><p>$

$\longrightarrow \sf\bold{\red{T_{10} =\: 17}}$

\therefore∴ The 10th term of an AP is 17.

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Answer 2

Answer:

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