Math, asked by fallenangle17d, 28 days ago

Q1. The H.C.F of two numbers is 23 and their LC.M is 1449. If one of the number
is 161. Find the other."
a) 507
b) 300
c) 207
d) 600​

Answers

Answered by shashirajgupta7
0

Step-by-step explanation:

hcfxlcm=product of numbers

23x1449=161x

x=23x1449/161

=207

Answered by Flaunt
190

Given

HCF of two numbers is 23

LCM of two numbers is 1449

One number is 161

To Find

The other number

\sf\huge\bold{\underline{\underline{{Solution}}}}

Let us assume that the second number be 'x'

first number is given which is 161.

We know that :

By properties of LCM and HCF:-

HCF×LCM =Product of two numbers

=>23×1449=161×x

=>33327=161x

=>x=33327÷161

=>x=207

Therefore,the other number is 207

Check

HCF ×LCM=Product of two numbers

=>23×1449=161×207

=>33327=33327

Extra information=>

LCM(least common multiple) is the least or smallest Common multiple of any two number (natural)

e.g., 10,15,20 LCM will be 60

Note :60 is divisible by all.

HCF (highest common factor) is the highest factor of any two given numbers (natural)

e.g., 10 =>2×5

15=>3×5

20=>2×5×2

here,the common factor is 5 and it is the HCF .

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