Question

Q1 The nth terms of the AP a, 3a, 5a --------is
Ans (2n+1)a​

Answer 1

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Answer 2

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a = a .

d = 3a - a = 2a .

So, ${n}^{th}$ term

$a_{n} = a + ( n - 1 ) d$

$a_{n} = a + ( n - 1 ) 2a$

Taking a as common , we get ,

$a_{n} = a ( 1 + 2n - 2 )$

$a_{n} = a ( 2n + 1 )$