Q1) the odometer of a car reads 57321. 0 km when the clock shows the time 8:30 a.m. what is the distance moved by the car , if at 8:50 a.m., the odometer reading has changed to 5733 6.0 km? Calculate the speed of the car in kilometre minute during this time Express the speed in kilometre/hour also.
Q2) Salma takes 15 minutes from her house to reach her school on a bicycle if the bicycle has speed of 2 metre /s,calculate the distance between her house and the school.
Answers
Answered by
4
Answer:
Distance traveled = 15 km
speed in km/min = 0.75 km/min
And speed in km/h = 45 km/hr
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1800 m or 1.8 km
Explanation:
Initial reading of odometer = 57321 km
Final Reading = 57336
Hence, distance traveled = 57336 - 57321 = 15 km
Time between 8:30 and 8:50 AM = 20 min or 20/60 = 1/3 hrs
So, speed in km/min = 15/20 = 3/4 = 0.75 km/min
And speed in km/h = 15 ₊ 1/3 = 15 * 3 = 45 km/hr
______________________________________
Time taken = 15 min = 15*60 = 900 s
Speed = 2 m/s
So, distance = speed * time = 2 * 900 = 1800 m or 1800/1000 km = 1.8 km
Answered by
0
Answer:
I think the upper answer is right
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