Question

Q1. The roots of quadratic question are 3y^2 + ky + 12 = 0 are real and equal, then find the value of k...

@bijaychoudhary302 thanks buddy​

Answer 1

Answer:

k=12

Step-by-step explanation:

Given the roots of the equation is equal and real.

So,

D=0

b^2-4ac=0

k^2-4*3*12=0

k^2-144=0

k^2=144

k=√144=12