Math, asked by popatmalaviyaxd, 2 months ago

Q1 The roots of the quadratic
polynomial 2x^2 + x - 3 = 0 are
x = 1 &x= -3/2
x = 1 & X = 3/2

x = -1 & x = 3/2
x = 1 & x = -3​

Answers

Answered by shirishapurushotham3
1

Answer:

2x^2-2x+3x-3

2x(x-1)+3(x-1)

(x-1)(2x+3)

x=1 | x= -3/2

Answered by laxmiyadav82
0

Answer:

X= 1 & -3/2

Step-by-step explanation:

2x²+x-3= 0

2x²+ 3x-2x -3 = 0

X(2x+3) -1 (2x+3)= 0

(x-1) (2x+3)= 0

x-1=0 & 2x+3= 0

X=1 & X = -3/2

Similar questions