Math, asked by itzcuteprincess32, 18 days ago

Q1.The sides of a triangle are 25cm, 39cm and 56cm respectively. Find the Given terms : ( I ) Area of the Triangle. ( II ) The altitude to the longest side of the Triangle.​


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Answers

Answered by PRINCE100001
5

Answer:

mere liye

Step-by-step explanation:

Step-by-step explanation:

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The sides of a triangle are 25cm, 39cm and 56cm respectively.

Find the Given terms :

( I ) Area of the Triangle.

( II ) The altitude to the longest side of the Triangle.

↓Answer↓

i) Area of ∆ :

p = (25 + 39 + 56) ÷ 2 = 60

Area = √(60)(60-25)(60-39)(60-56)

Area = √176400

Area = 420 cm²

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ii) Find the altitude:

Area = 1/2 x base x height

420 = 1/2 x 56 x height

420 = 28 x height

height = 420 ÷ 28

height = 15 cm

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Therefore, Area Of the ∆ will be 420cm²

and Altitude of ∆ will be 15cm.

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Hope it will be Helpful

Thankyou

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