Q1.the sum of the zeroes of the polynomial 2x² + 3 kx + 3 is 10, the
I the value of k.
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Step-by-step explanation:
Given
We have given sum of the zeroes of the polynomial 2x²+3kx+3 is 10
To Find
we have to find the value of k
Let λ,β & δ be the zeroes of the given polynomial
then ,λ,β + δ
Sum of zeroes = coefficient of x / coefficient of x²
λ+β + δ = -b/a = coefficient of x / coefficient of x²
λ+β + δ = -b/a = - 3k/2
Given sum of zeroes is 10
So, λ+β + δ = -b/a = 10
=> -3k/2= 10
=> 10*2= -3k
=> k= - 20 /3
More information=>
If λ,β & δ are the zeroes then product of zeroes = c/a = constant term / coefficient of x²
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