Math, asked by Paramjeet59921, 20 days ago

Q1 ) The tank contains 1000 gal of water in which 200lb of salt are dissolved. Fifty gal of brine, each containing (1+ cost) lb of dissolved salt, run into the tank per minute.The mixture, kept uniform by stirring, runs out at the same rate. Find the amount of salt y(t) in the tank at any time t . Q.2) Find an integrating factor and then solve.
y' = xy +2x - x^3, y(0)=0 Also find the 3rd approximated solution by Picard’s method.

Answers

Answered by sidhantpratapsingh35
0

A tank contains 1000 gal of water in which 200 lb of salt are dissolved. Fifty gal of

brine, each containing (1 cost) lb of dissolved salt, run into the tank per minute.

The mixture, kept uniform by stirring, runs out at the same rate. Find the amount of

salt y(t) in the tank at any time t

Answered by lakshmilakku
0

Answer:

constantly being stirred

Step-by-step explanation:

1000 gal of water in a tank has 200 pound of salt dissolved in it. The tank is filled with 50 gal of brine per minute, each holding 1 cost kg of dissolved salt.

The mixture runs out evenly since it is constantly being stirred. Find the tank's salt content y(t) at any time t.

and do the formulated procedure finaly gets

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