Question

Q1. The two Zeroes of a Qladuatic polynomial are-4 and -6.find the sum and product of the zeroes. What is the
value of coefficient b? ​

Answer 1

Step-by-step explanation:

Sum of zeroes = (-4) + (-6)

= (-10)

Product of zeroes = (-4)*(-6)

= 24

We know equation is in form of x

$a {x}^{2} + bx \: + c \: = 0$

$a {x}^{2} +(sum \: of \: zeroes)x \: + product \: of \: zeroes \: = 0$

comparing

we get b = (-10)