Question

Q1.The value of x when the distance between the points (7, x) and (4,0) is 5 units is a. +7 b. O c. +4 d. 3
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Answer 1

Step-by-step explanation:

SOLUTION

TO CHOOSE THE CORRECT OPTION

The value of x when the distance between the points (7, x) and (4,0) is 5 units is

a. +7

b. O

c. +4

d. 3

CONCEPT TO BE IMPLEMENTED

For the given two points

$\sf{A( x_1 , y_1) \: \: and \: \: B( x_2 , y_2)}</p><p> \: the \: distance \: between \: the \: points$

$= \sf{ \sqrt{ {(x_2 -x_1 )}^{2} + {(y_2 -y_1 )}^{2} } }</p><p>$

EVALUATION

Here the given points are (7, x) and (4,0)

So by the given condition

$\sf{ \sqrt{ {(7 - 4)}^{2} + {(x - 0)}^{2} } = 5} </p><p>$

$\sf{ \implies \: \sqrt{ {(3)}^{2} + {(x )}^{2} } = 5}</p><p>$

$\sf{ \implies \: {(3)}^{2} + {(x )}^{2} = 25}$

$\sf{ \implies \: {(x )}^{2} = 16}$

⟹x=4

FINAL ANSWER

Hence the correct option is c. + 4

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