Q1.The velocity -time graph of SUV is given abow The mass of the SUV is 1000 kg.
a) Find out the distance travelled by the SUV in each section A. B, C, D.
b) What is the total distance travelled by the SUV?
Please refer to the picture above
Answers
Required solution:
a) Find out the distance travelled by the SUV in each section A, B, C and D.
~ Firstly calculating distance in A!
→ s = Area under curve
→ Distance = Area under curve
→ Distance = Area of triangle
→ Distance = ½ × B × H
→ Distance = ½ × (10-0) × (5-0)
→ Distance = ½ × 10 × 5
→ Distance = 1 × 5 × 5
→ Distance = 25 m in A!
~ Now calculating in section B!
→ s = Area under curve
→ Distance = Area under curve
→ Distance = Area of rectangle
→ Distance = Length × Breadth
→ Distance = (30-10) × (5-0)
→ Distance = 20 × 5
→ Distance = 100 m in B!
~ Now calculating in C section!
→ s = Area under curve
→ Distance = Area under curve
→ Distance = Area of trapezium
→ Distance = (Sum of || heights)/2 × h
→ Distance = (5+15)/2 × (40-30)
→ Distance = 20/2 × 10
→ Distance = 10 × 10
→ Distance = 100 m in C!
~ Now let us calculate distance in D!
→ s = Area under curve
→ Distance = Area under curve
→ Distance = Area of triangle
→ Distance = ½ × B × H
→ Distance = ½ × (50-40) × (15-0)
→ Distance = ½ × 10 × 15
→ Distance = 1 × 5 × 15
→ Distance = 75 m in D!
b) What is the total distance travelled by the SUV?
→ Total distance = Distance of A + Distance of B + Distance of C + Distance of D
→ Total distance = 25 + 100 + 100 + 75
→ Total distance = 25 + 200 + 75
→ Total distance = 100 + 200
→ Total distance = 300 m