Question

Q1) Two mirrors MM' and NM' meet at right angles. An incident ray falls on NM' at an angle of 40° as shown in figure below. M 40° TITIT M N a) b) c) d) What is the angle of reflection of the ray incident on NM' at an angle of 40°? At which angle the ray reflected by NM' is incident on MM'? A reflected ray can be reflected again. How this figure proves it correct? Draw the reflected ray from MM'. Draw the reflected ray from NM'. e)​

Answer 1

Answer:

Angle of deviation in case of double reflection is given as  

       δ=360°−2θ

=360°−2(40°)

=360°−80°

=280°

Answer 2

Answer:

The correct answer of this question is 280°.

Explanation:

Given -  Two mirrors MM' and NM' meet at right angles and  incident ray falls on NM' at an angle of 40°.

To Find - Write  what is the angle of reflection of the ray incident on NM' at an angle of 40°

In the case of twofold reflection, the angle of deviation is given as,

δ=360°−2θ

=360°−2(40°)

=360°−80°

=280°

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