Physics, asked by vshouryansh6, 1 month ago

Q1.Two point charges, QA = +10C and QB = +12C, are separated by a distance r = 5cm. What is the magnitude of the electric force.
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Answers

Answered by haldertarun864

0

Answer:

240N

Explanation:

F = QA * QB÷r^2N

F = 10* 12÷0.5^2N ( 5cm = 0.5m)

F = 240N

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