Question

Q1. Two small ants of length 2 cm and 1.8 cm crawl in opposite directions with average speeds of 0.003 and 0.002 meters per second respectively. How many seconds will they take to cross each other?​

Answer 1

Step-by-step explanation:

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Answer 2

Answer:

Here we will find the time to take to cross the two ants to each other using the given length and average speed value.

Time to take to cross the two ants to each other $=7.6seconds$

Step-by-step explanation:

For calculate the time to take cross each other using the following formula,

                       $Time =\frac{Distance}{Speed }$

For this sum,

                       $Time =\frac{Sum of length}{Sum of Average speed}$

That is,           $Time =\frac{length of ant1 + length of ant2}{average speed1+average speed2}$

Distance (or) length = length of ant1 + length of 2

                                  $=2+1.8$

Distance (or) length  $=3.8cm$

In our question, speed in meter per second. So that, length should be change from centimeter to meter.

So that,              $100cm=1m$  

                          $3.8cm=\frac{3.8}{100}$

                          $3.8cm=0.038m$

Distance (or) length   $=0.038m$

Similarly, next find the Sum of average speeds. That is,

                       Speed = average speed 1 + average speed 2

                                   $=0.003+0.002$

                       Speed $=0.005m$

Next we can find the Time to take to cross the two ants to each other. So that, already we know the formula,

                           $Time =\frac{Distance}{Speed }$

                                   $=\frac{0.038}{0.005}$

now divide $0.038$ and $0.005$.Then we will get the following answer,

                         Time  $=7.6seconds$