Question

Q1.two years ago dilip was three times as old is his son and two years hence twice his age will be equal to five times that of his son ,find their present ages?​

Answer 1

Explanation:

Given :-

Two years ago dilip was three times as old is his son and two years hence twice his age

To Find :-

Present ages

Solution :-

Let the son age be x

Age of father = 3x

Two years ago

Age of son = x - 2

Age of father = 3(x - 2)

Now

After 2 years

Age of son = x + 2

Age of father = 3(x - 2) + 2 = 3x - 6 + 2 = 3x - 4

ATQ

5(x+2) = 2(3x - 2)5(x+2)=2(3x−2)

5x + 10=6x-45x+10=6x−4

6x - 5x = 10 + 46x−5x=10+4

x=14x=14

Age of son = 14 years

Age of father = 3(14) - 4 = 42 - 4 = 38 years