Math, asked by pandeyyuvraj2018, 4 months ago

Q1. Two years ago, the age of A was three times the age of B. If B is currently 9 years old, then after how many years, the age of A will be double of the age of B?

(a) 2 years
(b) 3 years
(c) 4 years
(d) 5 years​

Answers

Answered by saisobusy
3

Answer:

5 years

Step-by-step explanation:

present age of A=x    B=9

two years ago means B age is 7 and A s age three times B i.e, 21

therfore present age of A is 23 B is 9

finally after 5 years, age of A is 28 and B s age is 1

Where the age of A Is double the age of B

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