Question

Q1 Use identity to solve

(2y -5) (2y-5)​

Answer 1

( 2y - 5 ) ( 2y - 5 )

( 2y - 5 ) ²

4y² - 20y + 25

Answer 2

Answer:

the identity is

(a-b)^2 =a^2 - 2ab + b^2

(2y-5)^2 = 2y^2 - 2×2y×5+5^2

= 4y^2 - 20y + 25

this is the answer..

hope it helps u