Question

Q1.using all factors method find H.C.F of each:-


(1).32,48,16

(2).36.48,96

Answer 1

Answer:

We will now calculate the prime factors of 32 and 48, than find the greatest common factor (greatest common divisor (gcd)) of the numbers by matching the biggest common factor of 32 and 48.

Answer 2

Answer:

$hello \\ \\ 32 = 2 \times 2 \times 2 \times 2 \times 2 \\48 = 2 \times 2 \times 2 \times 2 \times 3 \\ 16 = 2 \times 2 \times 2 \times 2 \times 1 \\ hence \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \\ hcf =2 \times 2 \times 2 \times 2 = 16 \\ \\ \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \36 = 2 \times 2 \times 3 \times 3 \\ \\ 48 = 2 \times 2 \times 2 \times 3 \times 2\\ \\ 96 = 2 \times 2 \times 2 \times 2 \times 2 \times 3 \\ hcf = 2 \times 2 \times 3 = 12$