Question

Q1.what impluse is needed to stop a ball of mass 200g travelling a velocity 110 kmph​

Answer 1

Explanation:

Giventhat

✠ Mass of ball = 200 grams.

✠ Velocity of ball = 110 km/h

To find

✠ Impulse needed to stop the ball.

Solution

USING FORMULA

✠ Impulse needed to stop the ball = 6.112 kg.m/s.

Using concept

✠ ∆P (To find impulse)

✠ Impulse = m∆v

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~ As it's already given that the mass of the ball is 200 grams. Means let's convert gram into kilogram firstly.

✨ Converting g into kg

➙ 1 kg = 1000 grams

➙ 1 gram = 1/1000 kg

➙ 200 grams = 200/1000

➙ 0.2 kilograms

_______________________

~ It is also given that it is travelling with a velocity of 110 km/h so let's convert it into m/s.

✨ Converting km/h into m/s

➙ 110 km/h = (5/18) = 550/18

➙ Velocity = 30.56 m/s

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~ It is also given that the ball is about to stop henceforth, it's final velocity be 0 m/s by itself..!

✨ Let's apply the formula..!

➙ ∆P = m∆v

➙ ∆P = 0.2(0)-0.2(30.56)

➙ ∆P = 0-6.112

➙ ∆P = -6.112

But we haven't to take impulse as negative so let's take it as positive..!

➙ ∆P = 6.112 kg.m/s

_______________________

Answer 2

Answer:

here I post the similar que and ans refer it bro!

Explanation:

A hockey ball of mass 200 g travelling at 10 ms

−1

is struck by a hockey stick so as to return it along its original path with a velocity of 5 ms

−1

. Calculate the change of momentum which occurred in the motion of the hockey ball by the force applied by the hockey stick:

ans.. −3 Ns

Mass of ball(m)=200g=0.2kg

Initial velocity of ball(u)=10ms

−1

Final velocity of ball(v)=5ms

−1

Therefore, change in momentum (△p) = Final momentum - initial momentum =m(v−u)=0.2×(−5−10)=−3 kgms

−1

=−3 Ns