Q1.What is the frequency of rotation of a body rotating under a force of F = 100N, tied to a sting of length L =
2m and mass of 8g. Your answer should be correct to one decimal.
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Step-by-step explanation:
Given :
Centripetal force = 100 N
Length of string = 2 m
Mass of the body = 8 g = 0.008 kg
To Find :
Frequency of rotation of a body.
Solution :
Centripetal force acting on a body of mass m moving at a velocity of v in the circle of radius r is given by
Relation between linear velocity and angular velocity is given by; v = r ω
We know that :: ω = 2π f
where f denotes frequency of rotation
By substituting the given values;
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