Question

Q1. What is the sum of the following expression? 1 + 3 + 5 + ... + 103
a)
2704 b) 2809 c) 2601 d) 2500​

Answer 1

Answer:

this is an AP with first term 1, last term 103 and common difference 2

first we find number of terms

an=a+(n-1)d

103=1+(n-1)2

102=2(n-1)

n-1=51

n=52 therefore 52 terms

sum of AP = n/2 ( 2a + (n-1)d )

= 52/2 ( 2×1 + 51d )

= 26 ( 2 + 102 )

= 26 × 104

= 2704

option A is the answer

Answer 2

Answer:

.... =103-5-3-1=94

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