Question

Q1. Write down the output ofthefollowing: a) int a = 10: System.out.println(a++ ): System.out.println(++a J;a+=2; System.out.println(a): b) System.out.println((int)3.14);​

Answer 1

Question:-

Write down the output of the following:-

a) int a = 10;

System.out.println(a++);

System.out.println(++a);

System.out.println(a);

b) System.out.println((int)3.14));

Solution:-

a) Output :

10

12

12

b) Output :

3

Reason:-

a)

int a = 10

= Variable a has an assigned value 10.

a++

= This is a postfix increment. The rule of postfix increment is to first use , then increment.

So, the value of a++ remains same due to the rule.

//Now the value of a is 11 because of postfix law i.e., first use then increment. So the value of a++ will be 10 and after that, the current value of a will be incremented by 1 .

++a

= This is a prefix increment. The rule of prefix increment is to first increment then use.

So, the value of ++a will be 12.

//Now the value of a is 12.

a

= 12

b)

(int) 3.14

= We can see that the value has a decimal point i.e., it's data type is double data type.

This is a explicit type conversion.

So, when converting a double data type to int data type using explicit conversion , the output will be in the assigned data type.

Syntax:-

(data-type) expression

For example :-

double x = 3.14;

int y ;

y = (int) x;

Output : 3