Question

Q1. Write the balanced chemical equations for the following reactions and identify the type of reaction in each case.

(a) Nitrogen gas is treated with hydrogen gas in the presence of a catalyst at 773 K to form ammonia gas.

(b) Sodium hydroxide solution is treated with acetic acid to form sodium acetate and water.

(c) Ethanol is warmed with ethanoic acid to form ethyl acetate in the presence of concentrated H2SO4.

(d) Ethene is burnt in the presence of oxygen to form carbon dioxide, water and releases heat and light.


**Give full reaction detail & equation.
**I will mark brillianest to the best and full answer.

Answer 1

Ans: (a) Nitrogen gas is treated with hydrogen gas in the presence of a catalyst at 773K to 

form ammonia gas. 
N2 + 3H2 (773K)→2NH3
(b) Sodium hydroxide solution is treated with acetic acid to form sodium acetate and 

water. 
NaOH + CH3COOH → CH3COONa + H2O
 
(c) Ethanol is warmed with ethanoic acid to form ethyl acetate in the presence of 

concentrated H2SO4.
C2H5OH + CH3COOH+ (Conc.H2SO4) → CH3COOC2H5 + H2O
(d) Ethene is burnt in the presence of oxygen to form carbon dioxide, water and releases 

heat and light.
CH2=CH2 + 3O2 → 2CO2 + 2H2O + Light + heat