Q1.Write (x-1/2)² in the expanded form.
Q2.Find the value of a , if (x-1) is a factor of 2x²+ax+√2
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Q1.
⇒(x-1/2)²⇒(x-1/2)(x-1/2)⇒x²-x/2-x/2+1/4
⇒x²-x+1/4
Q2.
given x-1 is a factor so the equation should satisfy 1
substitute x=1 and equate it to 0
⇒2(1)²+a(1)+√2=0
⇒2+a+√2=0
⇒a=-2-√2
⇒(x-1/2)²⇒(x-1/2)(x-1/2)⇒x²-x/2-x/2+1/4
⇒x²-x+1/4
Q2.
given x-1 is a factor so the equation should satisfy 1
substitute x=1 and equate it to 0
⇒2(1)²+a(1)+√2=0
⇒2+a+√2=0
⇒a=-2-√2
Vaishnavi18:
thank u!!!
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