Question

Q10. A body starts with an
initial velocity of 20 m/s and
acceleration of 10 m/s^2. Find
the distance covered by it in
10s.​

Answer 1

given that

u=20m/s

a=10m/s^2

t=10sec

by using second equation of motion

s=ut+1/2at^2

s= 20×10 + 1/2×10×100

s=200+500

s=700

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Answer 2

s=ut+1/2at$^{2}$

s=20*10+1/2*10*10*10

s=200+500

s=700