Question

Q10) A cylinder made up of wood (s=0.6)
of diameter D and the length 2D is
suspended in water with its axis vertical.
State the condition of equilibrium
+​

Answer 1

Explanation:

For neutral equilibrium, GM = 0 (M coinciding with G)

Hence,

               \frac { L }{ D } \quad =\quad \frac { 1 }{ \sqrt { 8S\left( 1\quad -\quad S \right) } }DL=8S(1−S)1

Given specific gravity = 0.6  

               \frac { L }{ D } \quad =\quad \frac { 1 }{ \sqrt { 8\quad \times \quad 0.6\quad \left( 1\quad -\quad 0.6 \right) } }DL=8×0.6(1−0.6)1

               =\quad \frac { 1 }{ \sqrt { 8\quad \times \quad 0.6\quad \times \quad 0.4 } }=8×0.6×0.41

               \frac { L }{ D } \quad =\quad \frac { 1 }{ 8\sqrt { 0.03 } }DL=80.03