Math, asked by gayatrishrivastava13, 4 months ago

Q10. A door of length 2 m and breadth 1
m is fitted in a wall. The length of wall is
4.5 m and breadth is 3.6 m. Find the cost
of painting the wall at the rate of Rs. 20/
Sq.m
O 284
O 248
O 324
O 364

Plz tell the answer fast​

Answers

Answered by ParkJina
1

Answer:

284

Length of door = 2

Breadth of door = 1

Area = 2m²

Length of wall = 4.5

Breadth of wall = 3.6

Area= 16.20

Area to be painted = 16.20 - 2 = 14.20

Cost of painting per m² = ₹20

Total cost = 14.20×20= 284

Answered by RishikaJha731820
0

Answer:

284

Step-by-step explanation:

ATQ:- Length of door = 2m

Breadth of door = 1m

So, the Area of door will be (l × b)

= (2×1)m^2 = 2m^2

Length of wall = 4.5m

Breadth of wall = 3.6m

So, the Area of door will be (l × b)

= (4.5 × 3.6)m^2 = 16.2m^2

Now, (Area of wall - Area of door)

= 16.2m^ - 2m^2 = 14.2m^2

Cost of painting the wall at rate of Rs. 20/m^2

= Rs. (20 × 14.2)

= Rs. 284

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